Materi 4 Pendekatan Sistem dalam Pemecahan Masalah ~ Ahmad Muhsin Blog's

Selasa, 06 Oktober 2015

Materi 4 Pendekatan Sistem dalam Pemecahan Masalah

21.56 Pemodelan Sistem 264 comments

sumber gambar : www.edgefxkits.com

Permasalahan umum seperti :

PENGANGGURAN
KEMISKINAN
BUTA HURUF
VIRUS FLU BURUNG
INFLASI EKONOMI
DEMO BURUH
KEMACETAN
DLL

Permasalahan dalam Industri seperti :

PRODUK CACAT
KESULITAN PERIJINAN
KEKURANGAN BAHAN BAKU
KECELAKAAN KERJA
KEBISINGAN
MATI LISTIK
KINERJA TIDAK SEBANDING

Permasalahan dalam manufaktur seperti :

Memahami kerusakan komponen
Mengurangi adanya variasi dalam proses
Mengurangi biaya manufaktur
Meningkatkan pangsa pasar
Mendapatkan teknologi terbaik
Menemukan pengembangan produk baru

Pendekatan pemecalahan masalah dibagi 2 :
1. PENDEKATAN ANALISIS “Pendekatan perbagian”
2. PENDEKATAN SISTEM “Pendekatan menyeluruh”

Pendekatan sistem berati :

melihat permasalahan dalam konteks yang lebih luas, sehingga tidak dapat menjawab permasalahan dengan solusi yang terisolasi.
Pembelajaran (learning) berkaitan dengan steady state yang dinamis.

264 komentar:

Wahyu Surya R7 Oktober 2015 pukul 09.38
B_WAHYU SURYA RAHMAN_122130232
Diketahui :

 Zi-1 = Tanggal Lahir (11 mei 1995)
 A = 13
 C = 7
 M = 30 x 2 x Stasiun Kerja (1) = 60
 Zi = (axZi-1+c) mod m
• Z1 = (13 x 11 + 7) mod 60
= 150 mod 60
= 30
• Z2 = (13 x 30 + 7) mod 60
= 397 mod 60
= 37
• Z3 = (13 x 37 + 7) mod 60
= 488 mod 60
= 8
https://drive.google.com/open?id=0B5Cfj7QOyOLhYjlsazItR0oxN2M
BalasHapus
Balasan
Retno Ayu P.H9 Oktober 2015 pukul 05.55
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Irvan Dwi F9 Oktober 2015 pukul 20.58
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Nova Putri Kim Herdianti10 Oktober 2015 pukul 04.22
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown10 Oktober 2015 pukul 08.42
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown10 Oktober 2015 pukul 19.13
B_122130030_Danang Ibrahim Adnan

Zi-1 = 8 (tanggal lahir)
a = 13
C = 7
Mod = 30 x 2 x 1 = 60

Z(1) = (a x Zi-1 + C)
= (13 x 8 + 7) mod 60
= 111 mod 60
=51

Z(2) = (13 x 51 +7) mod 60
= 670 mod 60
= 10

Z(3) = (13 x 10 +7) mod 60
= 137 mod 60
= 17

https://drive.google.com/file/d/0B-zBJOsiLqULUEhSeHJVWVAzSzA/view?usp=sharing
BalasHapus
Balasan
Unknown10 Oktober 2015 pukul 20.04
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
brokensoul10 Oktober 2015 pukul 20.17
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown10 Oktober 2015 pukul 21.51
A_122130197_MAUDINA RACHMA DEWI

Zi-1 = 26 (tanggal lahir)
a = 13
C = 7
M = 30 x 2 x 2 = 120
Z(1) = (a x Zi-1 + C) mod m
= (13 x 26 + 7) mod 120
= 345 mod 120
= 105 ≈ 05
Z(2) = (a x Zi-1 + C) mod m
= (13 x 105 + 7) mod 120
= 1372 mod 120
= 52
Z(3) = (a x Zi-1 + C) mod m
= (13 x 52 + 7) mod 120
= 683 mod 120
= 83

https://drive.google.com/file/d/0B07GrNmo-OC3YkN2Rms1YVAxUEE/view?usp=sharing
BalasHapus
Balasan
Mayda Adriati10 Oktober 2015 pukul 22.02
A_122130168_MAYDA ADRIATI

Zi-1= 8 (tanggal lahir)
a= 13
c= 7
m= 30x 2x 2= 120
Z(1)= (ax Zi-1 + c) mod m
=(13x8+7) mod 120
= 111 mod 120
= 111 = 11
Z(2)= (ax Zi-1 + c) mod m
=(13x111+7) mod 120
= 1450 mod 120
= 10
Z(3)= (ax Zi-1 + c) mod m
=(13x10+7) mod 120
= 137 mod 120
= 17

https://drive.google.com/file/d/0B_zfzR1bCiyXa1o3bldxRE1vblU/view?usp=sharing
BalasHapus
Balasan
Muhamad Yoga Pratama11 Oktober 2015 pukul 02.31
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
rahmaah11 Oktober 2015 pukul 07.16
D - 122130011 - Rahmah Nur Jayanti

tanggal lahir : 29
Zi-1 = 29
a = 13
c = 7
m = 30x2x1(stasiun kerja)

Z(1) = (13.29+7) mod 60
= 384 mod 60
= 24

Z(2) = (13.24+7) mod 60
= 319 mod 60
= 19

Z(3) = (13.19+7) mod 60
= 254 mod 60
= 14

https://drive.google.com/open?id=0B4s85lbXy1IOWDlKSENVNjF3T28
BalasHapus
Balasan
brokensoul11 Oktober 2015 pukul 07.25
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 07.53
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 07.55
B_122130222_Nanda Agung Yuwana

Zi-1 = 26 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 3(stasiun Kerja) = 180

Z(1)= (a x Zi-1 + c) mod m
=(13 x 26 + 7) mod 180
= 345 mod 180
= 165

Z(2) = (a x Zi-1 + C) mod m
= (13 x 265 + 7) mod 180
= 3452 mod 180
= 172

Z(3) = (a x Zi-1 + C) mod m
= (13 x 172 + 7) mod 180
= 2243 mod 180
= 83

https://drive.google.com/file/d/0B5cfe9lZtziSOTl2akVTV3E4NTA/view?usp=sharing
BalasHapus
Balasan
Naufal Rizqulloh11 Oktober 2015 pukul 08.06
B_122130058_Naufal Rizqulloh Muharam

Zi-1 = 13 (tanggal lahir)
a = 13
C = 7
Mod = 30 x 2 x 1 = 60

Z(1) = (a x Zi-1 + C)
= (13 x 13 + 7) mod 60
= 176 mod 60
=56

Z(2) = (13 x 56 +7) mod 60
= 735 mod 60
= 15

Z(3) = (13 x 15 +7) mod 60
= 202 mod 60
= 22

https://drive.google.com/file/d/0B6BGFZLobTmDalBvYXVpUk1CTHM/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 08.12
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 08.17
B_ZERIQO HAMZAH AMBIYA_122130203
 Zi-1 = Tanggal Lahir (13 oktober 1995)
 A = 13
 C = 7
 M = 30 x 2 x Stasiun Kerja (1) = 60
 Zi = (axZi-1+c) mod m
• Z1 = (13 x 13 + 7) mod 60
= 176 mod 60
= 56
• Z2 = (13 x 56 + 7) mod 60
= 735 mod 60
= 15
• Z3 = (13 x 15 + 7) mod 60
= 202 mod 60
= 22
https://drive.google.com/open?id=0B39LMf8GGARPMlNleFBIUXRUYnM
BalasHapus
Balasan
Eryan Mahendra Putra11 Oktober 2015 pukul 08.55
A – 122130250 – Eryan Mahendra Putra

tugas 5
Tanggal lahir (28)
Zi-1 = 28
a = 13
c = 7
m = 30 x 2 x 2 =120
Zi = (a x Zi-1 + c) mod m
Z1 = (13 x 28 +7) mod 120 = 371 mod 120 = 11
Z2 = (13 x 11 +7) mod 120 = 150 mod 120 = 30
Z3 = (13 x 30 +7) mod 120 = 397 mod 120 = 37

https://drive.google.com/file/d/0B3SpP2JPXtvkSkJNZHdHU2tEc1U/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 08.56
A_122130243_Diah Galih Nurhikmatul Jannah

diketahui
Zi-1 = 30 (tgl lahir)
a = 13
c = 7
m = 30 x 2 x jml SK = 30 x 2 x 3 = 180
Z1 = (a x Zi-1 + c) mod m
= (13 x 30 + 7) mod 180
= 397 mod 180
= 37
Z2 = (a x Zi-1 + c) mod m
= (13 x 37 + 7) mod 180
= 488 mod 180
= 128 = 28
Z3 = (a x Zi-1 + c) mod m
= (13 x 128 + 7) mod 180
= 1671 mod 180
= 51

https://drive.google.com/open?id=0BxbZLDVLrOt2VjcwQzY2ZmVUU0E
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 09.04
A - 122130264 - Iqbal Rendragraha

Zi-1 = 8 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

Z(1)= (a x Zi-1 + c) mod m
=(13 x 8 + 7) mod
= 111 mod 60
= 51

Z(2) = (a x Zi-1 + C) mod m
= (13 x 51 + 7) mod 60
= 670 mod 60
= 10

Z(3) = (a x Zi-1 + C) mod m
= (13 x 10 + 7) mod 60
= 137 mod 60
= 17

https://drive.google.com/open?id=0B-2DJ4FNIxz2RmxVcVJhMUVFTlk
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 09.07
A_122130194_Aditya Abdillah Humaidi

Dik :
- Z(i-1) = 17 (tanggal lahir)
- a = 13
- c = 7
- m = 30 x 2 x 1 = 60
Zi = (a x Zi-1 + c) mod m
Z1 = (13 x 17 +7) mod 60 = 228 mod 60 = 48
Z2 = (13 x 48 +7) mod 60 = 631 mod 60 = 31
Z3 = (13 x 31 +7) mod 60 = 410 mod 60 = 50

https://drive.google.com/file/d/0Bz90opp1SVw7bmFnaU5lX2lsaDA/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 09.25
B - 122130279 - Muhammad Agung Susanto

Keterangan

Zi-1 = 8 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

z1= (13 x 8 + 7) mod 60
z1= (111) mod 60
z1 = 51

z2= (13 x 51+ 7) mod 60
z2= (670) mod 60
z2 = 10

z3= (13 x 10+ 7) mod 60
z3= (137) mod 60
z3 = 17

https://drive.google.com/file/d/0B1EzXcDICK59U2ZROTR3MHB5WFk/view
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 09.28
B_AAN TRIHINDARTO_122130219

Diketahui :

-Zi-1 = Tanggal Lahir (23 JUNI 1995)
-A = 13
-C = 7
-M = 30 x 2 x Stasiun Kerja (1) = 60
-Zi = (axZi-1+c) mod m
1. Z1 = (13 x 23 + 7) mod 60
= 306 mod 60
= 6
2. Z2 = (13 x 6 + 7) mod 60
= 85 mod 60
= 25
3. Z3 = (13 x 25 + 7) mod 60
= 332 mod 60
= 32

https://drive.google.com/file/d/0B06kw9YHtMSrOHVIcmtKTWx1UWs/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 09.36
A - 122130266 - Niken Rega Artika

diketahui
Zi -1 = 16 (tanggal lahir)
a = 13
c = 7
m = 30 x 2 x jml SK = 30 x 2 x 3 = 180
Z1 = (a x Zi-1 + c) mod m
= (13 x 16 + 7) mod 180
= 215 mod 180
= 35

Z2 = (a x Zi-1 + c) mod m
= (13 x 35 + 7) mod 180
= 462 mod 180
= 102
Z3 = (a x Zi-1 + c) mod m
= (13 x 102 + 7) mod 180
= 1333 mod 180
= 73

https://drive.google.com/file/d/0B5rJcSzqU4PlOXlmYi1EdFZKWDg/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 10.04
A_122130248_Ria Melliyana Purba

Zi-1 = 7 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 1 = 60

Z1 = (a x Zi-1 + c) mod M
= (13 x 7 + 7) mod 60
= 38

Z2 = (a x Zi-1 + c) mod M
= (13 x 38 +7) mod 60
= 21

Z3 = (a x Zi-1 + c) mod M
= (13 x 21 + 7) mod 60
= 40

https://drive.google.com/open?id=0B0jx_vrxYRCOVXhoMGs2dVJwVEE
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 10.21
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 10.26
B-122130225-Gigih Jono Prasetio

Pembangkitan Bil. Random
Zi=(aZi-1+C)Mod M
Dimana, a = 13
C = 7
M = 240
Zi-1 = 31 (tanggal lahir)
• Z(1) = ( 13 . 31 + 7 ) mod 240 = 410 mod 240 = 170
• Z(2) = ( 13 . 170 + 7 ) mod 240 = 2217 mod 240 = 57
• Z(3) = ( 13 . 57 + 7 ) mod 240 = 748 mod 240 = 28

https://drive.google.com/file/d/0B1RvTOj6sB5nNWFNQkU4TVZNb3M/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 12.42
A_122130256_Wayan Rendy Armilando

Zi-1 = 26 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 1 = 60

Z1 = (a x Zi-1 + c) mod M
= (13 x 26 + 7) mod 60
= 45

Z2 = (a x Zi-1 + c) mod M
= (13 x 45 +7) mod 60
= 52

Z3 = (a x Zi-1 + c) mod M
= (13 x 52 + 7) mod 60
= 23

https://drive.google.com/file/d/0B5lM4Ky3KtvJbWd6VldpRURON1k/view?usp=sharing
BalasHapus
Balasan
Qta Homestay11 Oktober 2015 pukul 14.01
Kelas B - 122130184 - Febri Trianto

tanggal lahir : 17
Zi-1 = 17
a = 13
c = 7
m = 30 x 2 x 5 (stasiun kerja) = 300

Z(1) = (13 x 17 + 7) mod 300 = 228 mod 300 = 228
Z(2) = (13 x 228 + 7) mod 300 = 2971 mod 300 = 271
Z(3) = (13 x 271 + 7) mod 300 = 3530 mod 300 = 230

https://drive.google.com/file/d/0BwEuZjYM2cB7VTFTczk0aEdXbzA/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 16.49
B_ DANAR TEGUH SANTOSO _122130231

 Zi-1 = Tanggal Lahir (26 MARET 1995)
 A = 13
 C = 7
 M = 30 x 2 x Stasiun Kerja (5) = 300
 Zi = (axZi-1+c) mod m
• Z1 = (13 x 26 + 7) mod 300
= 345 mod 300
= 45
• Z2 = (13 x 45 + 7) mod 300
= 592 mod 300
= 292
• Z3 = (13 x 292 + 7) mod 300
= 3.803 mod 300
= 203

https://drive.google.com/open?id=0B48ONm2ViCG8NDNBS0Y5XzhCc28
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 17.26
A - 122130220 - Aulia Arlaga Vantrica

diketahui
Zi -1 = 15 (tanggal lahir)
a = 13
c = 7
m = 30 x 2 x jml SK = 30 x 2 x 3 = 180
Z1 = (a x Zi-1 + c) mod m
= (13 x 15 + 7) mod 180
= 202 mod 180
= 22

Z2 = (a x Zi-1 + c) mod m
= (13 x 22 + 7) mod 180
= 293 mod 180
= 113

Z3 = (a x Zi-1 + c) mod m
= (13 x 113 + 7) mod 180
= 1476 mod 180
= 36

https://drive.google.com/file/d/0Bwr-KNH-GbIXUTQ4eHc1OUh2ak0/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 17.29
A – 122130254 – Eka Wulandari

Tanggal lahir 10
Zi-1 = 10
a = 13
c = 7
M = 30 x 2 x jumlah SK = 30 x 2 x 2 =120
Zi = (a x Zi-1 + c) mod m
Z1 = (13 x 10 +7) mod 120
= 137 mod 120
= 17
Z2 = (13 x 17 +7) mod 120
= 228 mod 120
= 108 =8
Z3 = (13 x 108 +7) mod 120
= 1411 mod 120
=91

https://drive.google.com/file/d/0B3SpP2JPXtvkclczZDBES0MwUFk/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 17.36
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 17.36
B-122130116-Olivia Oktariska Timbayo

Tugas 5
Zi = (a.Zi-1 + c) mod m
Zi-1 = 31 (tanggal lahir)
a = 13
c = 7
m = 30 x 2 x SK => SK= 2 yaitu produksi dan pengemasan
m = 120

Teknik membangkitkan bilangan random
Z1 = (13. 31 + 7) mod 120
Z1 = 410 mod 120
Z1 = 50

Z2 = (13. 50 + 7) mod 120
Z2 = 657 mod 120
Z2 = 57

Z3 = (13. 57 + 7) mod 120
Z3 = 748 mod 120
Z3 = 28

dan untuk tabelnya terlampir di
https://drive.google.com/file/d/0B0HOHot1gG8da0RFR3NjeHFaQ2M/view?usp=sharing
BalasHapus
Balasan
Unknown11 Oktober 2015 pukul 18.40
A_122130173_Mirna Lusyanna Veronika Nababan

Diketahui :
Zi-1 = 6 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 3(stasiun Kerja) = 180

Z(1)= (a x Zi-1 + c) mod m
=(13 x 6 + 7) mod 180
= 85 mod 180
= 85

Z(2) = (a x Zi-1 + C) mod m
= (13 x 85 + 7) mod 180
= 1112 mod 180
= 32

Z(3) = (a x Zi-1 + C) mod m
= (13 x 32 + 7) mod 180
= 423 mod 180
= 63

https://drive.google.com/file/d/0Bww87grCQzvMODFoOTRlSWgtZ0k/view?usp=sharing
BalasHapus
Balasan
Unknown12 Oktober 2015 pukul 05.11
A – 122130236 – Wislanda Hilman Al Haqim

Tugas 5
Zi-1 = 3 (tanggal lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

Z(1)= (a x Zi-1 + c) mod m
=(13 x 3 + 7) mod 60
= 46 mod 60
= 46

Z(2) = (a x Zi-1 + C) mod m
= (13 x 46 + 7) mod 60
= 605 mod 60
= 5

Z(3) = (a x Zi-1 + C) mod m
= (13 x 5 + 7) mod 60
= 12 mod 60
= 12

https://drive.google.com/file/d/0B96PUatRVjBNSFN4QlFldkZrQWs/view?usp=sharing
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 03.20
C_122130227_YUNITA CHRISTIANI

Untuk Teknik Pembangkitan Bilangan Random (Z1, Z2 dan Z3) terlampir dalam file berikut
https://drive.google.com/file/d/0B3Iz3gHblfDXSzljMUE0RVhYcDg/view?usp=sharing
BalasHapus
Balasan
Irvan Dwi F13 Oktober 2015 pukul 06.03
A-122130201-Irvan D. Fitriansyah
Zi-1 = 4 (tanggal lahir)
a = 13
c = 7
m = 30 x 2 x 3(stasiun Kerja) = 180

Z(1)= (a x Zi-1 + c) mod m
=(13 x 4 + 7) mod 180
= 59 mod 180
= 59

Z(2) = (a x Zi-1 + C) mod m
= (13 x 59 + 7) mod 180
= 774 mod 180
= 54

Z(3) = (a x Zi-1 + C) mod m
= (13 x 54 + 7) mod 180
= 709 mod 180
= 169

https://drive.google.com/file/d/0B0eC0P7vHWMfYlRYRjRCVXhjeVk/view?usp=sharing
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 07.07
D - 122130027 - Ina Martini

https://drive.google.com/open?id=0BwI2nXNo_qAzRmZmUlhzdXAwcGs
https://drive.google.com/open?id=0BwI2nXNo_qAzNVljZExVT2hVTkU
BalasHapus
Balasan
Risqi Setianingrum13 Oktober 2015 pukul 07.31
A_122130117_Risqi Setianingrum

Zi-1 = 11 (tanggal lahir)
a = 13
c = 7
m = 30.2.2 = 120

Z(1) = (a.zi-1+c) mod m
= (13.11+7) mod 120
= 150 mod 120
= 30

Z(2) = (13.30+7) mod 120
= 397 mod 120
= 37

Z(3) = (13.37+7) mod 120
= 488 mod 120
= 8

https://drive.google.com/open?id=0BytnTzuZ65PZd2pMeXZBZFdJNlU
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 07.32
D_122130180_Ngurah Nyoman Wisnu Setiawan

Perhitungan Z1, Z2, dan Z3 sudah ada di dalam file.

https://drive.google.com/file/d/0B1cIUt7OL2-qLUlKTmtsUkE2ODg/view?usp=sharing
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 07.33
D_122130180_Ngurah Nyoman Wisnu Setiawan

Perhitungan Z1, Z2, dan Z3 sudah ada di dalam file.

https://drive.google.com/file/d/0B1cIUt7OL2-qLUlKTmtsUkE2ODg/view?usp=sharing
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 10.43
D - 122130055 - Mita Indah Pramudita

https://drive.google.com/file/d/0B0Hso6pGFwWpWlp1aDBNSDdyT1k/view?usp=sharing
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 20.34
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 20.41
D-122130026-Nur Endah Fitriana

Tanggal lahir: 23
Zi-1 = 23
a = 13
c = 7
M = 30x2x1 stasiun kerja = 60

Z1 = (a x Zi-1 + c) mod 60
= (13 x 23 + 7) mod 60
= 306 mod 60
= 6

Z2 = (a x Zi-1 + c) mod 60
= (13 x 6 + 7) mod 60
= 85 mod 60
= 25

Z3 = (a x Zi-1 + c) mod 60
= (13 x 25 + 7) mod 60
= 332 mod 60
= 32

https://drive.google.com/file/d/0B6NQaewX16T-dmV2QlNSU1JZRDA/view
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 20.45
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 21.09
C - 122130245 - Sarah ustwatun khasanah

tugas 5

Zi-1 = 15 (tanggal lahir)
a = 13
C = 7
Mod = 30 x 2 x 1 = 60
(1) Z(1) = (a x Zi-1 + C)
= (13 x 15 + 7) mod 60
= 202 mod 60
=22
(2) Z(2) = (a x Zi-1 + C)
= (13 x 22 + 7) mod 60
=293 mod 60
=53
(3) Z(3) = (a x Zi-1 + C)
= (13 x 53 + 7) mod 60
=696 mod 60
=36
(4) Z(4) = (a x Zi-1 + C)
= (13 x 36 + 7) mod 60
=475 mod 60
=55

https://drive.google.com/file/d/0B42WMTCJL9mWUmdGQmp6LWhSVUU/view?usp=sharing
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 21.14
C - 122130072 - Rizki anggar permadi
tugas 5 pemodelan sistem

Zi-1 = 20 (tanggal lahir)
a = 13
C = 7
Mod = 30 x 2 x 1 = 60

(1) Z(1) = (a x Zi-1 + C)
= (13 x 20 + 7) mod 60
= 267 mod 60
=27

(2) Z(2) = (a x Zi-1 + C)
= (13 x 27 + 7) mod 60
=358 mod 60
=58

(3) Z(3) = (a x Zi-1 + C)
= (13 x 58 + 7) mod 60
=761 mod 60
=41

(4) Z(4) = (a x Zi-1 + C)
= (13 x 41 + 7) mod 60
=540 mod 60
=0

https://drive.google.com/file/d/0B00carAakxJ9bTY5cG84ekhsMnc/view?usp=sharing
BalasHapus
Balasan
Muhamad Yoga Pratama13 Oktober 2015 pukul 21.18
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 21.40
D - Gita Karmani - 122130023

Zi-1 = 21
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 1 = 60

Z(1) = ((13.21) + 7) mod 60
= 280 mod 60
= 40
Z(2) = ((13.40) + 7) mod 60
= 527 mod 60
= 47
Z(3) = ((13.47) + 7 mod 60
= 618 mod 60
= 18

https://drive.google.com/file/d/0B8C1p2ng2no1b1FNWUxqQktuMVk/view?usp=sharing
BalasHapus
Balasan
Unknown13 Oktober 2015 pukul 21.50
D_122130037_Herditya Mahardika

tanggal lahir : 16
Zi-1 = 16
a = 13
c = 7r
m = 30x2x1(stasiun kerja) = 60

Z(1) = (13.16+7) mod 60
= 215 mod 60
= 35

Z(2) = (13.35+7) mod 60
= 462 mod 60
= 42

Z(3) = (13.42+7) mod 60
= 553 mod 60
= 13

https://drive.google.com/file/d/0B6LKM_Ul-orJYk9naE8zT1YtUmc/view?usp=docslist_api
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 00.16
A_122130176_Redha Anggraeni Nilamsari

tanggal lahir saya : 24 juli 1994
jumlah stasiun kerja : 2 SK

Zi-1 = 24
a = 13
c = 7
m = 30x2x2 = 120

Z(1) = (13.24+7) mod 120
= 319 mod 120
= 79

Z(2) = (13.79+7) mod 120
= 1034 mod 120
= 74

Z(3) = (13.74+7) mod 120
= 969 mod 120
= 9
https://drive.google.com/file/d/0B9UTWfLNWtb9Y3FZNWFIZ2pMWFk/view?usp=sharing
BalasHapus
Balasan
Muhammad S Iqbal14 Oktober 2015 pukul 00.44
A_122130240_Muhammad Shahrani Iqbal
Keterangan
tanggal lahir : 11
a= 13
c = 7
m= 30 x 2 x SK = 30 x 2 x 2 = 120

Zi = (a x Zi-1 + c) mod 120
Z1= (13 x 11 + 7) mod 120
= 150 mod 120 = 30
Z2 = (13 x 30 + 7) mod 120
= 397 mod 120 = 37
Z3 = (13 x 37 + 7) mod 120
= 488 mod 120 = 8

https://drive.google.com/file/d/0B7j7itXVOTmNanBxdEdiZmM2bG8/view?usp=sharing
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 01.46
C - 122130036 - Diva Vanesha
Zi-1= 11 (tanggal lahir)
a= 13
c= 7
m= 30x 2x 2= 120
Z(1)= (ax Zi-1 + c) mod m
=(13 x 11 + 7) mod 120
= 150 mod 120
= 30

Z(2)= (ax Zi-1 + c) mod m
=(13 x 30 + 7) mod 120
= 397 mod 120
= 37

Z(3)= (ax Zi-1 + c) mod m
=(13 x 37 + 7) mod 120
= 488 mod 120
= 8

https://drive.google.com/file/d/0B3jVadZYLAv1VTVPc1JtZHROSFE/view?usp=sharing
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 02.58
E_122130215_Hera Rianti

https://drive.google.com/file/d/0B4Srj-TNqeZuVEF4dGwtMFVTTFE/view
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 04.43
E_122130214_Ika Dyah Permanaputri

https://drive.google.com/file/d/0B69vvY2MV63CUldQb0FVTEVoMm8/view?usp=sharing
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 05.50
D_122130028_Ambar Kusumasari

Zi-1 = 11 (tanggal lahir)
a = 13
c = 7
m = 30 x 2 x sk = 30 x 2 x 1 = 60

Z(1) = (13 x 11) + 7 mod 60
= 150 mod 60
= 30

Z(2) = (13 x 30) +7 mod 60
= 397 mod 60
= 37

Z(3) = (13 x 37) + 7 mod 60
= 488 mod 60
= 8

https://drive.google.com/file/d/0B4F079Q4swtXaXpsWGNROGRZTE0/view?usp=sharing
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 06.17
D_122130155_Aries T.R.

Zi-1 = 31(Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 1 = 60

Z1 = (13 x 31) + 7 mod 60
= 410 mod 60
= 50

Z2 = (13 x 50) + 7 mod 60
= 657 mod 60
= 57

Z3 = (13 x 57) + 7 mod 60
=748 mod 60
=28

https://drive.google.com/file/d/0Bxe70vellsGDNHVmTThVX0JVakk/view?usp=sharing
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 07.01
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 07.04
M = 30 x 2 x 1 = 60
Tanggal lahir = 5
Z(1) = (13.5+7) mod 60
= 72 mod 60
= 12

Z(2) = (13.12+7) mod 60
= 163 mod 60
= 43

Z(3) = (13.43+7) mod 60
= 556 mod 60
= 26
https://drive.google.com/file/d/0B6r4KjAHsSmaNUZscEozT1E5U0U/view?usp=docslist_api
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 07.05
M = 30 x 2 x 1 = 60
Tanggal lahir = 5
Z(1) = (13.5+7) mod 60
= 72 mod 60
= 12

Z(2) = (13.12+7) mod 60
= 163 mod 60
= 43

Z(3) = (13.43+7) mod 60
= 556 mod 60
= 26
https://drive.google.com/file/d/0B6r4KjAHsSmaNUZscEozT1E5U0U/view?usp=docslist_api
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 07.09
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 07.18
D_122130038_Alivian Vickry S
https://drive.google.com/file/d/0B5ZHwGu7v3hfelhqTEhBSlNSTGc/view?usp=sharing
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 08.26
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown14 Oktober 2015 pukul 16.31
D_122130014_CHEKA PUTRI MAHARANI

Perhitungan
M = 30 x 2 x 1 = 60
Z(1) = (13.23+7) mod 60
= 306 mod 60
= 6

Z(2) = (13.6+7) mod 60
= 85 mod 60
= 25

Z(3) = (13.25+7) mod 60
= 332 mod 60
= 32

https://www.dropbox.com/s/qlp4dcxyz2m8q3g/TUGAS4_CHEKA_122130014.docx?dl=0
BalasHapus
Balasan
Avidito Rio S14 Oktober 2015 pukul 21.50
Avidito Rio Saputra_122130207_B

M = 30 x 2 x 2 = 120
.
Z1 = (a. Zi-1+C) MOD 120
= 33 MOD 120
= 33

Z2 = (a. Z2-1+c ) MOD 120
= 436 MOD 120
= 76

Z3 = ( a.Z3-1+ C ) MOD 120
= 995 MOD 120
= 35

https://drive.google.com/file/d/0B6O-u4Oq76RzLVRpNTgteVhVQnc/view?usp=sharing
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 01.01
E_122130056_Denni Muhammad Darda

M = 30 x 2 x 1 = 60

Z1 = (a . Z1-1 + C) MOD 60
= (13 . 16 + 7) MOD 60
= 215 MOD 60
= 35

Z2 = (13 . 35 + 7) MOD 60
= 462 MOD 60
= 42

Z3 = (13 . 42 + 7) MOD 60
= 553 MOD 60
= 13

https://drive.google.com/file/d/0B0Vu635chwH0QlZGdWFPOTlSU2c/view?usp=sharing
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 01.09
C_122130031_Della Ayu Avianna

Zi-1 = 1 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 1 (jumlah SK) = 60

Z(1) = (axZi - 1 + c) MOD 60
= ( 13 x 1 x 7 ) MOD 60
= 20

Z(2) = (axZi - 1 + c) MOD 60
= (13 x 20 + 7) MOD 60
= 27

Z(3) = (axZi - 1 + c) MOD 60
= (13 x 27 + 7) MOD 60
= 58

https://drive.google.com/file/d/0B4flyB4uSyDPdm05MEdHSkRsSDA/view
BalasHapus
Balasan
icirai15 Oktober 2015 pukul 02.34
https://drive.google.com/file/d/0B1NCAHq5fYHnQlZIWjY3Uy1xLTg/view?usp=sharing
BalasHapus
Balasan
icirai15 Oktober 2015 pukul 02.35
E_122130050_Rizza Dwi Nusita

https://drive.google.com/file/d/0B1NCAHq5fYHnQlZIWjY3Uy1xLTg/view?usp=sharing
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 03.47
E-122130242-Indra Setiawan

https://drive.google.com/open?id=0B1krnS_FjmGoX2l6T2UtX0FSRzQ
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 04.31
E_122130191_Husnia Dina Amalia

https://drive.google.com/file/d/0BytFXSWqUOkGMDVXdC0wcXc5TDQ/view
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 04.32
C – 122130070 – Erfan Erdyanto

Zi – 1 = 15 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 3 (jumlah SK) = 180

Z(1) = (a x Zi – 1 + c) mod m
= (13 x 15 + 7) mod 180
= 202 mod 180
= 22

Z(2) = (a x Zi – 1 + c) mod m
= (13 x 22 + 7) mod 180
= 293 mod 180
= 113

Z(3) = (a x Zi – 1 + c) mod m
= (13 x 113 + 7) mod 180
= 1476 mod 180
= 36

https://drive.google.com/file/d/0B9k-xBVs8GkwaC1DMURVRGJHSlU/view?usp=sharing
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 05.26
Nama : Tamyiz Munindra
NPM : 122130066
Kelas : C

Zi – 1 = 17 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 3 (jumlah SK) = 180

Z(1) = (a x Zi – 1 + c) mod m
= (13 x 17 + 7) mod 180
= 228 mod 180
= 48

Z(2) = (a x Zi – 1 + c) mod m
= (13 x 48 + 7) mod 180
= 631 mod 180
= 91

Z(3) = (a x Zi – 1 + c) mod m
= (13 x 91 + 7) mod 180
= 1190 mod 180
= 110

https://drive.google.com/file/d/0B6c1f5JtmjIIYjVxVVl6TTk4QjQ/view?usp=sharing
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 06.42
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 08.26
D_122130106_ferdinan goring

Zi – 1 = 15 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 1 (jumlah SK) = 60

Z(1) = (a x Zi – 1 + c) mod m
= (13 x 15 + 7) mod 60
= 202 mod 60
= 22

Z(2) = (a x Zi – 1 + c) mod m
= (13 x 22 + 7) mod 60
= 293 mod 60
= 53

Z(3) = (a x Zi – 1 + c) mod m
= (13 x 53 + 7) mod 60
= 696 mod 60
= 36

https://drive.google.com/file/d/0BwfmS0lYGN_2eE5lQlN1UVFJSVk/view?usp=sharing
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 11.03
E - 122130274 - Aziz Munizar Rusyda

Zi-1 = 31 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

Z(1)= (a x Zi-1 + c) mod m
=(13 x 31 + 7) mod
= 410 mod 60
= 50

Z(2) = (a x Zi-1 + C) mod m
= (13 x 50 + 7) mod 60
= 657 mod 60
= 57

Z(3) = (a x Zi-1 + C) mod m
= (13 x 57 + 7) mod 60
= 748 mod 60
= 28

https://drive.google.com/file/d/0B9Jbq1Xs-gOkTjRDNlZWOVM5NFk/view?usp=sharing
BalasHapus
Balasan
Unknown15 Oktober 2015 pukul 19.56
Zi-1 = 6 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

Z(1)= (a x Zi-1 + c) mod m
=(13 x 6 + 7) mod 60
= 85 mod 60
= 25

Z(2) = (a x Zi-1 + C) mod m
= (13 x 25 + 7) mod 60
= 332 mod 60
= 32

Z(3) = (a x Zi-1 + C) mod m
= (13 x 32 + 7) mod 60
= 423 mod 60
= 3

https://drive.google.com/file/d/0B8E6VQ17AoGjNHExMkVlaHdvczA/view?usp=sharing
BalasHapus
Balasan
Unknown16 Oktober 2015 pukul 03.46
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown16 Oktober 2015 pukul 04.29
A - 122130124 - Fayakun Akbar

Zi-1 = 22 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 2(stasiun Kerja) = 120

Z(1)= (a x Zi-1 + c) mod m
=(13 x 22 + 7) mod 120
= 293 mod 120
= 53

Z(2) = (a x Zi-1 + C) mod m
= (13 x 53 + 7) mod 120
= 696 mod 120
= 96

Z(3) = (a x Zi-1 + C) mod m
= (13 x 96 + 7) mod 120
= 1255 mod 120
= 55

https://drive.google.com/file/d/0BzgLeynHxfm7SGVCVDN6MXRiWGs/view?usp=sharing
BalasHapus
Balasan
Unknown16 Oktober 2015 pukul 05.49
B_122130019_SHINTA PUSPITA

Perhitungan
M = 30 x 2 x 2 = 120
Tanggal lahir = 16

Z(1) = (13.16+7) mod 120
= 215 mod 120
= 95

Z(2) = (13.95+7) mod 120
= 1242 mod 120
= 42

Z(3) = (13.42+7) mod 120
= 553 mod 120
= 73

https://drive.google.com/file/d/0BzEorok7r9e1UFNfdXNHRUZBMjQ/view
BalasHapus
Balasan
Unknown16 Oktober 2015 pukul 07.00
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown16 Oktober 2015 pukul 07.02
D_122130255_Yulianto
Z1-1 = 19 (tanggal lahir)
a = 13
C = 7
m = 30 x 2 x 2 ( jumlah SK) = 120

Z(1) = (a . Zi-1 + C) mod m
= (13 . 19 + 7) mod 120
= 254 mod 120
= 14

Z(2) = (a . Zi-1 + C) mod m
= (13 . 14 + 7) mod 120
=189 mod 120
= 69

Z(3) = (a . Zi-1 + C) mod m
= (13. 69 + 7) mod 120
= 904 mod 120
= 64

https://drive.google.com/file/d/0Bz6176MPgNHgRHN0ek9VcERBaDA/view?usp=sharing
BalasHapus
Balasan
Unknown16 Oktober 2015 pukul 08.23
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown16 Oktober 2015 pukul 08.33
B_122130202_M. Aminudin Risqianto
Tugas 5
Contoh perhitngan Z1, Z2 dan Z3 ada di dalam file
https://drive.google.com/file/d/0BxfXW-HwP6HqSnRROUZ0Z3hDZFU/view?usp=sharing
BalasHapus
Balasan
kevin16 Oktober 2015 pukul 12.24
D_122130200_Kevin Stefanus

Zi-1 = 21
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 1 = 60

Z(1) = ((13.21) + 7) mod 60
= 280 mod 60
= 40
Z(2) = ((13.40) + 7) mod 60
= 527 mod 60
= 47
Z(3) = ((13.47) + 7 mod 60
= 618 mod 60
= 18

https://drive.google.com/file/d/0B9xDlFF_p-adTEVnaG5VSkk3T28/view?usp=sharing
BalasHapus
Balasan
Unknown16 Oktober 2015 pukul 15.38
D-122130057-Rifqi Naufal Rafif
Zi-1 = 18
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 1 = 60

Z(1) = ((13.18) + 7) mod 60
= 241 mod 60
= 1
Z(2) = ((13.1) + 7) mod 60
=20 mod 60
=20
Z(3) = ((13.20) + 7 mod 60
= 267 mod 60
= 27

https://drive.google.com/open?id=0B8B-LJEXlMJmTVNHS05HNW9seGM
BalasHapus
Balasan
Arif romadhon16 Oktober 2015 pukul 22.35
D_122130068_Arif Romadhon_Tugas 5

Z1 = Bilangan Random
Z0 24 (tanggal lahir)
a 13
c 7
m 30*2*1(jumlah stasiun kerja) = 60

Z(1) = (13.24 + 7) mod 60
= 319 mod 60
= 19
Z(2) = (13.19 + 7) mod 60
= 254 mod 60
= 14
Z(3) = ( 13. 14 + 7) mod 60
= 189 mod 60
= 9

https://www.dropbox.com/ow/msft/edit/home/Tugas%205.docx?hpt_click_ts=1445060076545
BalasHapus
Balasan
Unknown17 Oktober 2015 pukul 00.00
E_122130178_Fitri F.H Insyoraki

https://drive.google.com/file/d/0BwdH_To5byPnY0JBZG5Mc256dTA/view?usp=sharing
BalasHapus
Balasan
Unknown17 Oktober 2015 pukul 03.13
A-122130112-Adelin Siregar

Zi-1 = 28 (tgl lahir)
a = 13
c = 17
mod = 30 x 2 x jml SK = 30 x 2 x 2 = 120

Z1 = (a x Zi-1 + c) mod m
= (13 x 28 + 7) mod 120
= 371 mod 120
= 11
Z2 = (a x Zi-1 + c) mod m
= (13 x 11 + 7) mod 120
= 150 mod 120
= 30
Z3 = (a x Zi-1 + c) mod m
= (13 x 30 + 7) mod 120
= 397 mod 120
= 37

https://drive.google.com/open?id=0B0UbWDYgLWWjbzNrZFJmU0pWR0U
BalasHapus
Balasan
Firraart17 Oktober 2015 pukul 06.46
A_122130091_FIRRA APRINDANTI (TUGAS 5)

Zi-1 = 3 (Tanggal Lahir)
a = 13
c = 17

M = 30 x 2 x 1 = 60
Z(1) = (13.3+7) mod 60
= 46 mod 60
= 46

Z(2) = (13.46+7) mod 60
= 605 mod 60
= 5

Z(3) = (13.5+7) mod 60
= 72 mod 60
= 12

https://drive.google.com/file/d/0B1CfKM7VUCTwQnB6c21TUHBWeG8/view?usp=sharing
BalasHapus
Balasan
Unknown17 Oktober 2015 pukul 07.33
E - 122130253 - Safira Ratnasari

Zi-1 = 10 (Tanggal Lahir)
a = 13
c = 17

M = 30 x 2 x 2 = 120

Z(1) = (13.10 + 7) mod 120
= 137 mod 120
= 17

Z(2) = (13.17 + 7) mod 120
= 228 mod 120
= 108

Z(3) = (13.108 + 7) mod 120
= 1411 mod 120
= 91

https://drive.google.com/file/d/0B1nUyzIi_3TTNm9JUTRTWWUtdGM/view?usp=sharing
BalasHapus
Balasan
Unknown17 Oktober 2015 pukul 07.40
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown17 Oktober 2015 pukul 18.04
B - 122130189 - Widya Nurul Shofa
data perhitungan ada didalam file
https://drive.google.com/file/d/0B_WczazoY5Y6LUhQUXU1My1PY1U/view?usp=sharing
BalasHapus
Balasan
Unknown18 Oktober 2015 pukul 00.41
A - 122130002 - Faizal Ramadhan

Zi-1 = 12
a = 13
C = 7
M = 120

https://drive.google.com/file/d/0B7Nt37EWBX0ERnZMZTFuNU96ZVk/view?usp=sharing
BalasHapus
Balasan
Unknown18 Oktober 2015 pukul 02.05
D - 122130105 - Nugroho Noto Susanto

Keterangan:
tanggal lahir : 23
a= 13
c = 7
m= 30 x 2 x SK = 30 x 2 x 1 = 60

Zi = (a x Zi-1 + c) mod m

Z1= (13 x 23 + 7) mod 60 = 6
Z2 = (13 x 6 + 7) mod 60 = 25
Z3 = (13 x 25 + 7) mod 60 = 32

https://drive.google.com/file/d/0B-bIrJqs-y96V3hhNFIyQjkxNDQ/view?usp=sharing
BalasHapus
Balasan
Susi Dwi Rahayu18 Oktober 2015 pukul 03.28
A - 122130124 - SUSI DWI RAHAYU

Zi-1 = 24 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 4 (stasiun Kerja) = 240

Z(1)= (a x Zi-1 + c) mod m
=(13 x 24 + 7) mod 240
= 79

Z(2) = (a x Zi-1 + C) mod m
= (13 x 79 + 7) mod 240
= 74

Z(3) = (a x Zi-1 + C) mod m
= (13 x 74 + 7) mod 240
= 9

https://drive.google.com/file/d/0B934RFRrzxDlNUlPaGxOdWd1Yk0/view?usp=sharing
BalasHapus
Balasan
Unknown18 Oktober 2015 pukul 05.20
C - 122130077 - Evelina Nadia LIspriyantika

Zi-1 = 4
a = 13
c = 7
m = 30x2x1 = 60

Z(1) = (13x4+7) mod 60 = 59
Z(2) = (13x59+7) mod 60 = 54
Z(3) = (13x54+7) mod 60 = 49

https://drive.google.com/file/d/0BwTAjYL3FOiCdFh6QllGMlF4Rnc/view?usp=sharing
BalasHapus
Balasan
qatoqsueq18 Oktober 2015 pukul 12.00
A_122130071_Bambang Irawan

TUGAS : 5

Zi-1 = 7 (Tanggal lahir)
a = 13
C = 7
Mod = 13x2x1 =60
1) Z(1) = (axZi-1+C)
= (13x7+7) mod 60
= 98 mod 60
= 38
2) Z(2) = (axZi-1+C)
= (13x38+7) mod 60
= 501 mod 60
= 21
3) Z(3) = (axZi-1+C)
= (13x21+7) mod 60
= 280 mod 60
= 40

https://drive.google.com/file/d/0B_hM_tb76DnqZlNpd1lLb1RRSE0/view?usp=sharing
BalasHapus
Balasan
Unknown18 Oktober 2015 pukul 22.24
A_122130126_Milata Aji Permana

Tugas 5

Zi-1 = 2 (tanggal lahir)
a = 13
c = 7
m = 30x2x1 = 60

Z(1) = (13x2+7) mod 60 = 46
Z(2) = (13x46+7) mod 60 = 5
Z(3) = (13x5+7) mod 60 = 12

https://drive.google.com/file/d/0B1nnXey0i0fmMV91QVdPNjl0cjA/view?usp=sharing
BalasHapus
Balasan
Unknown19 Oktober 2015 pukul 00.03
E_122130047_Deby Agnatya Nugraha Putra

https://drive.google.com/file/d/0B0HOHot1gG8dbmZjTDAyd1k5OWc/view?usp=sharing
BalasHapus
Balasan
Unknown19 Oktober 2015 pukul 02.17
B_ 122130166_ I Nyoman Suwana Gita Kusuma

Zi-1 = 4 (tanggal lahir)
a = 13
C = 7
Mod = 30 x 2 x 1 = 60

Z(1) = (13.4+7) mod 60

= 59 mod 60

= 59

Z(2) = (13.59+7) mod 60

= 774 mod 60

= 54

Z(3) = (13.54+7) mod 60

= 709 mod 60

= 49

https://drive.google.com/file/d/0B9bpwb8IqrCjV3VmWElJa2VzYlE/view?usp=sharing
BalasHapus
Balasan
Unknown19 Oktober 2015 pukul 08.38
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown19 Oktober 2015 pukul 08.40
C_122130107_Anolvri Samaliwu

Zi-1 = 10 (tanggal lahir)
a = 13
C = 7
Mod = 30 x 2 x 1 = 60

Z(1) = (13.10+7) mod 60

= 137 mod 60

= 17

Z(2) = (13.17+7) mod 60

= 228 mod 60

= 48

Z(3) = (13.48+7) mod 60

= 631 mod 60

= 31

https://drive.google.com/file/d/0B2K-yoTwTVAWUjNfTE9IaTFTcDA/view?usp=sharing
BalasHapus
Balasan
Unknown19 Oktober 2015 pukul 10.04
D_ 122130043_ Rani Triyani

Zi-1 = 27 (tanggal lahir)
a = 13
c = 7
m = 30 x 2 x sk = 30 x 2 x 1 = 60

Z(1) = (13 x 27) + 7 mod 60
= 358 mod 60
= 58
Z(2) = (13 x 58) +7 mod 60
= 761 mod 60
= 41
Z(3) = (13 x 41 ) + 7 mod 60
= 540 mod 60
= 0

https://drive.google.com/file/d/0B1517mXnQLIZdlZ6WFk0bGlrNHM/view
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 02.13
C_1221302137_Gilang Fajar Pratama Suwarna

Zi-1 = 26 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 1 = 60

Z1 = (a x Zi-1 + c) mod M
= (13 x 26 + 7) mod 60
= 45

Z2 = (a x Zi-1 + c) mod M
= (13 x 45 +7) mod 60
= 52

Z3 = (a x Zi-1 + c) mod M
= (13 x 52 + 7) mod 60
= 23

https://drive.google.com/file/d/0B_CKe_A1O7GBZ1p3NHpwYzRIWHc/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 04.18
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 04.19
D_122130033_Dikri Machmul Kurniawan
a = pengali --> 13
c = increament --> 7
m = modus --> 30x2xjml SK=60
Zi-1 = 22(tanggal lahir)
Z1=(13*22+7)mod m
Z1=267 mod 60
Z1=53
Z2=(13*53+7)mod m
Z2=358 mod 60
Z2=36
Z3=(13*36+7)mod m
Z3=761 mod 60
Z3=55
https://drive.google.com/open?id=0B7BMX9szeWRSTkFTUVFPWFB0Z28

BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 04.22
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Kiki Rifqi20 Oktober 2015 pukul 04.38
C - 122130119 - ABIE FARABIE

Zi-1 = Tanggal Lahir 23
A = 13
C = 7
M = 30 x 2 x Stasiun Kerja (1) = 60
Zi = (axZi-1+c) mod m
1. Z1 = (13 x 23 + 7) mod 60
= 306 mod 60
= 6
2. Z2 = (13 x 6 + 7) mod 60
= 85 mod 60
= 25
3. Z3 = (13 x 25 + 7) mod 60
= 332 mod 60
= 32
https://drive.google.com/file/d/0B5FpOaEo_d5oQS16WjNBX2FlNmM/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 04.42
C - 122130172 - hisyam Dwi Satrio

Zi-1 = 21
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 1 = 60

Z(1) = ((13.21) + 7) mod 60
= 280 mod 60
= 40
Z(2) = ((13.40) + 7) mod 60
= 527 mod 60
= 47
Z(3) = ((13.47) + 7 mod 60
= 618 mod 60
= 18

https://drive.google.com/file/d/0BxDr-XpYzcyuZ2pGWFlhM0Q4VDg/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 05.04
Muhammad Ade Rafiyan_122130145_C

Zi-1 = Tanggal Lahir (26 NOVEMBER 1995)
A = 13
C = 7
M = 30 x 2 x Stasiun Kerja (5) = 300
 Zi = (axZi-1+c) mod m
• Z1 = (13 x 26 + 7) mod 300
= 345 mod 300
= 45
• Z2 = (13 x 45 + 7) mod 300
= 592 mod 300
= 292
• Z3 = (13 x 292 + 7) mod 300
= 3.803 mod 300
= 203

https://drive.google.com/file/d/0BxOs5JI1dYRecEdPYnU2c29wenM/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 05.19
Alga Febriansyah_122130162_C

Z1 = Bilangan Random
Z0 24 (tanggal lahir)
a 13
c 7
m 30*2*1(jumlah stasiun kerja) = 60

Z(1) = (13.24 + 7) mod 60
= 319 mod 60
= 19
Z(2) = (13.19 + 7) mod 60
= 254 mod 60
= 14
Z(3) = ( 13. 14 + 7) mod 60
= 189 mod 60
= 9

https://drive.google.com/file/d/0ByyW_wBqgG-FVFE1N2tJbGRHWGs/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 05.29
Z1 = Bilangan Random
Z0 24 (tanggal lahir)
a 13
c 7
m 30*2*1(jumlah stasiun kerja) = 60

Z(1) = (13.24 + 7) mod 60
= 319 mod 60
= 19
Z(2) = (13.19 + 7) mod 60
= 254 mod 60
= 14
Z(3) = ( 13. 14 + 7) mod 60
= 189 mod 60
= 9

https://drive.google.com/file/d/0By5uj3eexqB8YTVRUzB5dTEyREk/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 07.41
A_122130109_Made Piyan Hariyasa
Z1-1 = 19 (tanggal lahir)
a = 13
C = 7
m = 30 x 2 x 2 ( jumlah SK) = 120

Z(1) = (a . Zi-1 + C) mod m
= (13 . 19 + 7) mod 120
= 254 mod 120
= 14

Z(2) = (a . Zi-1 + C) mod m
= (13 . 14 + 7) mod 120
=189 mod 120
= 69

Z(3) = (a . Zi-1 + C) mod m
= (13. 69 + 7) mod 120
= 904 mod 120
= 64

https://drive.google.com/drive/my-drive
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 08.56
D - 122130048 - Ary Cahyadi

Zi-1 = 13
a = 13
C = 7
M = 120

https://drive.google.com/file/d/0B233pby_TiRHYURaSXFUaFdLb1k/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 09.05
C_122100143_M.Rifki.Hidayatullah
Zi-1 = 30
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 3 = 180
Z(i) = (a x Zi-1 +c) mod m
Z(1) = (13 x 30 + 7) mod 180
= 390 mod 180
= 20
Z(2) = (13 x 20 + 7) mod 180
= 260 mod 180
= 140
Z(3) = (13 x 20 + 7) mod 180
= 260 mod 180
= 150
https://drive.google.com/open?id=0B6cKBUCozCAEczNDNUxocmVoX2M
BalasHapus
Balasan
Faizal Amin20 Oktober 2015 pukul 09.47
C_122130118_Faizal Amin

https://drive.google.com/file/d/0B90yez3c6txUQlJaMUgxLUR1dEk/view?usp=sharing

BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 10.20
C_122130139_Dimas Tirta Nugraha

Zi-1 = 1(Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 1 = 60

Z1 = (13 x 1) + 7 mod 60
= 410 mod 60
= 50

Z2 = (13 x 50) + 7 mod 60
= 657 mod 60
= 57

Z3 = (13 x 57) + 7 mod 60
=748 mod 60
=28

https://drive.google.com/file/d/0B6HpxqyN0ZHkTVZYRjZoM01ScEU/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 11.26
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
sadam khoirul iman20 Oktober 2015 pukul 11.28
D_122130045_Sadam Khoirul Iman

Z1-1 = 19 (tanggal lahir)
a = 13
C = 7
m = 30 x 2 x 2 ( jumlah SK) = 120

Z(1) = (a . Zi-1 + C) mod m
= (13 . 19 + 7) mod 120
= 254 mod 120
= 14

Z(2) = (a . Zi-1 + C) mod m
= (13 . 14 + 7) mod 120
=189 mod 120
= 69

Z(3) = (a . Zi-1 + C) mod m
= (13. 69 + 7) mod 120
= 904 mod 120
= 64
https://drive.google.com/file/d/0BzOA1H2BuCQcSkdVbFZrY0xLOWM/view?usp=sharing
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 11.36
D -Satria Anung Wibawa - 122130095

Zi-1 = 21
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 1 = 60

Z(1) = ((13.21) + 7) mod 60
= 280 mod 60
= 40
Z(2) = ((13.40) + 7) mod 60
= 527 mod 60
= 47
Z(3) = ((13.47) + 7 mod 60
= 618 mod 60
= 18
https://drive.google.com/open?id=0B7PwDH0iqjshNFgzRHZmZ1BTSDQ
BalasHapus
Balasan
pradeas20 Oktober 2015 pukul 11.56
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 15.10
D_122130041_Husnan Yusuf

Perhitungan Manual
Z(1) (13.20+7) Mod m
20 Mod 60
20

Z(2) (13.20+7) Mod m
267 Mod 60
27

Z(3) (13.27+7) Mod m
358 Mod 60
58

https://www.dropbox.com/s/w74gis3ykz9gkow/PEMSIS%20ucup.xlsx?dl=0
BalasHapus
Balasan
felixzelin20 Oktober 2015 pukul 15.12
D_122130022_Felix Zelin Pradina

Perhitungan Manual
Z(1) (13.18+7) Mod m
391 Mod 60
19

Z(2) (13.19+7) Mod m
254 Mod 60
14

Z(3) (13.14+7) Mod m
189 Mod 60
9

Z(3) (13.27+7) Mod m
358 Mod 60
58

https://www.dropbox.com/s/6g4e9zatafkg9ut/PEMSIS%20felix.xlsx?dl=0
BalasHapus
Balasan
Unknown20 Oktober 2015 pukul 16.07
B_122130223_Zyan Kharisma
Tanggal lahir : 16 Januari 1995
Zi-1 = 16
A = 13
C = 7
M = 30x2xjumlah SK (2) = 120
Zi = (AxZi-1+C) MOD M
Z1 = (13x16+7) MOD 120
Z1 = 215 MOD 120
Z1 = 95
Z2 = (13x95+7) MOD 120
Z2 = 1242 MOD 120
Z2 = 42
Z3 = (13x42+7) MOD 120
Z3 = 553 MOD 120
Z3 = 73

https://drive.google.com/file/d/0B9Fln515-b3ZRnNOM1JUam5sMDQ/view?usp=sharing
BalasHapus
Balasan
Desmond21 Oktober 2015 pukul 06.05
A_122130271_Desmond V.A.P

Z1-1 = 19 (tanggal lahir)
a = 13
C = 7
m = 30 x 2 x 2 ( jumlah SK) = 120

Z(1) = (a . Zi-1 + C) mod m
= (13 . 19 + 7) mod 120
= 254 mod 120
= 14

Z(2) = (a . Zi-1 + C) mod m
= (13 . 14 + 7) mod 120
=189 mod 120
= 69

Z(3) = (a . Zi-1 + C) mod m
= (13. 69 + 7) mod 120
= 904 mod 120
= 64

https://drive.google.com/open?id=0B7FMdpvLYiBATk1haDdtcVZsRXM
BalasHapus
Balasan
Unknown21 Oktober 2015 pukul 08.03
D_122130085_ANDI PURNOMO_TUGAS 5

Z1-1 = 31 (tanggal lahir)
a = 13
C = 7
m = 30 x 2 x 1 ( jumlah SK) = 60

Z(1) = (a . Zi-1 + C) mod m
= (13 . 31 + 7) mod 60
= 410 mod 60
= 50

Z(2) = (a . Zi-1 + C) mod m
= (13 . 50 + 7) mod 60
= 657 mod 60
= 57

Z(3) = (a . Zi-1 + C) mod m
= (13. 57 + 7) mod 60
= 748 mod 60
= 28

https://drive.google.com/file/d/0B8Pj9M0CYRyxUE1iTmMzSDlsZWc/view?usp=sharing

BalasHapus
Balasan
Unknown21 Oktober 2015 pukul 08.48
A_122130179_Panji Putra Utama

Z1-1 = 15 (tanggal lahir)
a = 13
C = 7
m = 30 x 2 x 1 ( jumlah SK) = 60

Z(1) = (a . Zi-1 + C) mod m
= (13 . 15 + 7) mod 60
= 202 mod 60
= 22

Z(2) = (a . Zi-1 + C) mod m
= (13 . 22 + 7) mod 60
=293 mod 60
= 53

Z(3) = (a . Zi-1 + C) mod m
= (13. 53 + 7) mod 60
= 696 mod 60
= 36

https://drive.google.com/file/d/0B1HabF66o0uqT2JPOVhMTmExUjA/view?usp=sharing
BalasHapus
Balasan
Unknown21 Oktober 2015 pukul 09.02
B - 122130277 – Endinsya Irfa Nahara

Keterangan

Zi-1 = 26 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

z1= (13 x 26 + 7) mod 60
z1= (345) mod 60
z1 = 45

z2= (13 x 45+ 7) mod 60
z2= (592) mod 60
z2 = 52

z3= (13 x 52 + 7) mod 60
z3= (683) mod 60
z3 = 23
https://drive.google.com/file/d/0B9vgxJ4KA5uKU3VSbTdxaXB6TVE/view?usp=sharing
BalasHapus
Balasan
Unknown21 Oktober 2015 pukul 11.02
E_122130120_Kusfindri Puji N

Zi-1 = 26 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 1 = 60

Z1 = (a x Zi-1 + c) mod M
= (13 x 26 + 7) mod 60
= 45

Z2 = (a x Zi-1 + c) mod M
= (13 x 45 +7) mod 60
= 52

Z3 = (a x Zi-1 + c) mod M
= (13 x 52 + 7) mod 60
= 23
https://drive.google.com/file/d/0B7XLkUWTh09CUWVuRDRXNEFnSnM/view?usp=sharing
BalasHapus
Balasan
Unknown22 Oktober 2015 pukul 00.38
B_122130183_Tugas 5
https://drive.google.com/file/d/0B-N_LgQ12A43SEtBYmVydXExR1E/view?usp=sharing
BalasHapus
Balasan
Desmond22 Oktober 2015 pukul 03.49
D_122130230_Brian Pratama Situmorang

Tanggal Lahir : 16

M = 30 x 2 x 1 = 60

Z1 = (a . Z1-1 + C) MOD 60
= (13 . 16 + 7) MOD 60
= 215 MOD 60
= 35

Z2 = (13 . 35 + 7) MOD 60
= 462 MOD 60
= 42

Z3 = (13 . 42 + 7) MOD 60
= 553 MOD 60
= 13

https://drive.google.com/open?id=0B7FMdpvLYiBAQmI1Z3VabzFmMkE
BalasHapus
Balasan
brokensoul22 Oktober 2015 pukul 06.05
B_122130224_Anisa Damayanti

https://drive.google.com/file/d/0B3RmcjTowl_AenRQWHNVSHRaSzg/view?usp=sharing
BalasHapus
Balasan
sapto winarno22 Oktober 2015 pukul 18.22
A_ 122130177_Sapto Winarno
Tugas 5

Zi-1 = 22
a = 13
c = 7
m = 30x2x2(stasiun kerja)

Z(1) = (13.22+7) mod 120
= 293 mod 120
= 53

Z(2) = (13.53+7) mod 120
= 696 mod 120
= 96

Z(3) = (13.969+7) mod 120
= 1255 mod 120
= 55

https://drive.google.com/file/d/0B_jdqb1D6KYXbm52OEZrYW11RDQ/view?usp=sharing
BalasHapus
Balasan
Unknown22 Oktober 2015 pukul 20.27
B_122130161_Dicky Alghoni

Tugas 5

Tanggal Lahir : 16

M = 30 x 2 x 1 = 60

Z1 = (a . Z1-1 + C) MOD 60
= (13 . 16 + 7) MOD 60
= 215 MOD 60
= 35

Z2 = (13 . 35 + 7) MOD 60
= 462 MOD 60
= 42

Z3 = (13 . 42 + 7) MOD 60
= 553 MOD 60
= 13

https://drive.google.com/file/d/0B7sY865eRyDtQVE0anpQcTUzbVU/view?usp=sharing
BalasHapus
Balasan
Unknown23 Oktober 2015 pukul 02.54
A_122130127_Rizqi Wahyu Setiawan

Tugas 5

Tanggal Lahir : 1

Zi-1 = 1 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

z1= (13 x 1 + 7) mod 60
z1= (20) mod 60
z1 = 20

z2= (13 x 20+ 7) mod 60
z2= (267) mod 60
z2 = 27

z3= (13 x 27 + 7) mod 60
z3= (358) mod 60
z3 = 58

https://drive.google.com/file/d/0B3YAfZtAVrphUVZ2X0tqSVdMcWs/view?usp=sharing
BalasHapus
Balasan
Yudha Adhi Pradhana23 Oktober 2015 pukul 03.47
A_122130212_Yudha Adhi Pradhana

- Z(i-1) = 16 (tanggal lahir)
- a = 13
- c = 7
- m = 30 x 2 x 1 = 60

z1= (13 x 16 + 7) mod 60
z1= (215) mod 60
z1 = 35

z2= (13 x 35+ 7) mod 60
z2= (462) mod 60
z2 = 42

z3= (13 x 42 + 7) mod 60
z3= (553) mod 60
z3 = 13

https://drive.google.com/file/d/0B-rhkcnm8goNVTd6TlpIamxxUTQ/view?usp=sharing

BalasHapus
Balasan
Unknown23 Oktober 2015 pukul 08.08
B-122130121-Achmad zamroni
Tugas 5

Tanggal lahir : 3
Z-i= 3(tanggal lahir)
a = 13
c = 7
m = 30x2x1=60
 Z(1) = (13.3+7) mod 60
= 46 mod 60
= 46
 Z(2) = (13.46+7) mod 60
= 605 mod 60
= 5
 Z(3) = (13.5+7) mod 60
= 72 mod 60
= 12

https://drive.google.com/file/d/0B6N3PcZWBlxmVmllaUFmNk9RRkE/view?usp=sharing
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 01.21
C – 122130267 – Avian Wisnu Setiyoko

Zi – 1 = 19 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 2 (jumlah SK) = 120

Z(1) = (a x Zi – 1 + c) mod m
= (13 x 19 + 7) mod 120
= 254 mod 120
= 14

Z(2) = (a x Zi – 1 + c) mod m
= (13 x 14 + 7) mod 120
= 189 mod 120
= 69

Z(3) = (a x Zi – 1 + c) mod m
= (13 x 69 + 7) mod 120
= 904 mod 120
= 64

https://drive.google.com/file/d/0B_doboju6RcsWnZoUDJlcFQybUE/view?usp=sharing
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 01.23
Nama : Andra Dwi Prasetya
NPM : 122130065
Kelas : C

Zi – 1 = 16 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 2 (jumlah SK) = 120

Z(1) = (a x Zi – 1 + c) mod m
= (13 x 16 + 7) mod 120
= 215 mod 120
= 95

Z(2) = (a x Zi – 1 + c) mod m
= (13 x 95 + 7) mod 120
= 1242 mod 120
= 42

Z(3) = (a x Zi – 1 + c) mod m
= (13 x 42 + 7) mod 120
= 533 mod 120
= 73

https://drive.google.com/file/d/0Bzxiobh354p_WVNQZHVZcGdsRXM/view?usp=sharing
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 01.42
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 04.42
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 05.40
A_122130006_GABRILE HENSELIA

Zi – 1 = 6 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 2 (jumlah SK) = 120

Z(1) = (a x Zi – 1 + c) mod m
= (13 x 6 + 7) mod 120
= 85 mod 120
= 85

Z(2) = (a x Zi – 1 + c) mod m
= (13 x 85 + 7) mod 120
= 1112 mod 120
= 32

Z(3) = (a x Zi – 1 + c) mod m
= (13 x 32 + 7) mod 120
= 423 mod 120
= 63

https://drive.google.com/file/d/0B2NjYAudSepIZWwxMUZsei1LaDQ/view?usp=sharing

(REVISI)
BalasHapus
Balasan
rizqicoker24 Oktober 2015 pukul 09.59
A_122130234_Rizqi Dharmawan

Zi-1 = 24 (tanggal lahir)
a = 13
c = 7
m = 30x2x1(stasiun kerja) = 60

Z(1) = (13.24+7) mod 60
= 319 mod 60
= 19

Z(2) = (13.19+7) mod 60
= 254 mod 60
= 14

Z(3) = (13.14+7) mod 160
= 189 mod 60
= 9

https://drive.google.com/file/d/0BxxQC0N2f_saa0Z3MGQ4NGFNVFE/view?usp=sharing
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 12.39
A_122130258_Maulana Risakti

Revisi Tugas 5

Zi-1 = 1 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 1 (jumlah SK) = 60

Z(1) = (a.Zi - 1 + c) MOD 60
= ( 13 x 1 x 7 ) MOD 60
= 20

Z(2) = (a.Zi - 1 + c) MOD 60
= (13 x 20 + 7) MOD 60
= 27

Z(3) = (a.Zi - 1 + c) MOD 60
= (13 x 27 + 7) MOD 60
= 58

https://drive.google.com/file/d/0B0BVLvHRHGA7RDFueUhMT3lSd0U/view?usp=sharing
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 20.37
C_122130101_Rizekika Na'afi

a = 13
c = 7
Mod = 30 x 2 jumlah SK = 30 x 2 x 2 = 120
tanggal lahir = 24
Z(0) = 13 . 24 + 7 mod 120 = 79
Z(1) = 13 . 79 + 7 mod 120 = 74
Z(2) = 13 . 74 + 7 mod 120 = 9

https://drive.google.com/file/d/0B-gMPM9AFr2zOHZMOHMyUFlUNEk/view?usp=sharing
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 20.57
A_122130086_Dazzle Sixyries D

Zi-1 = 6 (tanggal lahir)
a = 13
c = 7
m = 30x2x2 = 120

Z(1) = (13.6+7) mod 120
= 85 mod 120
= 85

Z(2) = (13.85+7) mod 120
= 1111 mod 120
= 32

Z(3) = (13.63+7) mod 120
= 826 mod 120
= 63

https://drive.google.com/file/d/0B5YKwruWTEVwQzUtb3Yta0Z5b3M/view?usp=sharing
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 22.58
A_122130073_Muhammad Fauzan

Tugas 5

Tiga perhitungan awal
Z(1) = (13.16 + 7) mod 120
= 215 mod 120
= 95
Z(2) = (13.95 + 7) mod 120
= 1242 mod 120
= 42
Z(3) = ( 13. 42 + 7) mod 120
= 553 mod 120
= 73

https://drive.google.com/file/d/0B75dpWM71wPnWmV1SUU4V3c5UWM/view?usp=sharing
BalasHapus
Balasan
Unknown24 Oktober 2015 pukul 23.00
E_122130009_Diaz Putra Dwipantara

Zi-1 = 22 (tanggal lahir)
a = 13
c = 7
m = 30x1x2 = 60

Z(1) = (13.22+7) mod 60
= 293 mod 60
= 53

Z(2) = (13.53+7) mod 60
= 696 mod 60
= 36

Z(3) = (13.36+7) mod 60
= 475 mod 60
= 55

https://drive.google.com/open?id=0BxVPzgzkPVOiRHNpYmJwaElKdjg
BalasHapus
Balasan
Mucha prfile24 Oktober 2015 pukul 23.12
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Mucha prfile24 Oktober 2015 pukul 23.17
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Mucha prfile24 Oktober 2015 pukul 23.23
A-122130238-Mucharram
Diketahui :
Tanggal lahir11Juni 1994
Zi-1 = 11
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 3 = 180
Z(i) = (a x Zi-1 +c) mod m
Z(1) = (13 x 11 + 7) mod 180
= 150 mod 180
= 150
Z(2) = (13 x 150 + 7) mod 180
= 1957 mod 180
= 157
Z(3) = (13 x 157 + 7) mod 180
= 2048 mod 180
= 68

https://drive.google.com/file/d/0B7ngJwEgBQLiZUZULUFVb2lGcEk/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 00.01
C - 122130092 - Della Intan Saridewi

Zi – 1 = 8 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 3 (jumlah SK) = 180

Z(1) = (a x Zi – 1 + c) mod m
= (13 x 8 + 7) mod 180
= 111 mod 180
= 111

Z(2) = (a x Zi – 1 + c) mod m
= (13 x 111 + 7) mod 180
= 1450 mod 180
= 10

Z(3) = (a x Zi – 1 + c) mod m
= (13 x 10 + 7) mod 180
= 137 mod 180
= 137

https://drive.google.com/file/d/0BwQn-azwWAoiSDVvWkxYNk40Njg/view?usp=sharing

Catatan : Revisi pengiriman link karena yang kemarin tidak bisa dibuka.
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 03.48
Nama : Yudi Pratama Putra
NPM : 122130008
Kelas : C

Tugas 5

Zi – 1 = 28 (tanggal lahir)
A = 13
C = 7
M = 30 x 2 x 2 (jumlah SK) = 120

Z(1) = (a x Zi – 1 + c) mod m
= (13 x 28 + 7) mod 120
= 371 mod 120
= 11

Z(2) = (a x Zi – 1 + c) mod m
= (13 x 11 + 7) mod 120
= 150 mod 120
= 30

Z(3) = (a x Zi – 1 + c) mod m
= (13 x 30 + 7) mod 120
= 397 mod 120
= 37

https://drive.google.com/file/d/0BzT07Vpg0RYGNmxLektxTWRXUFU/view?usp=sharing

NB: Maaf telat pak, laptop saya rusak. terimakasih
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 03.56
E - 122130211 - Igent Galang Prasetyo

Tugas 5

Tiga perhitungan awal
Z(1) = (13.10 + 7) mod 120
= 200 mod 120
= 17
Z(2) = (13.17 + 7) mod 120
= 228 mod 120
= 108
Z(3) = ( 13.108 + 7) mod 120
= 1411 mod 120
= 91

https://drive.google.com/file/d/0Bz1z0DqWSwewdnNjazNXVkx0Q0U/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 04.25
B - 122130122 - Dwi Prasetyo Romadhon

Tugas 5

Zi – i = 1 (tanggal lahir)
a = 13
C = 7

Perhitungan:
M = 30 x 2 x 1 = 60
Z(1) = (13.1+7) mod 60
= 20 mod 60
= 20

Z(2) = (13.20+7) mod 60
= 267 mod 60
= 27

Z(3) = (13.27+7) mod 60
= 358 mod 60
= 58

https://drive.google.com/file/d/0B8KZOJmdWVlwTW1Kb3VHX3c1bEU/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 04.47
B_122130205_Dwi Prasetyo
https://drive.google.com/file/d/0B2qS5_LvnpODcF9KOV9lVFdiU2M/view?usp=sharing
BalasHapus
Balasan
aditya yusuf kiyen25 Oktober 2015 pukul 05.11
B_122130129_Aditya Yusuf Kiyen

Tugas 5

Zi-1 = 2 (tanggal lahir)
a = 13
c = 7
m = 30x2x1 = 60

Z(1) = (13x2+7) mod 60 = 46
Z(2) = (13x46+7) mod 60 = 5
Z(3) = (13x5+7) mod 60 = 12

https://drive.google.com/file/d/0B7CyNqTrEU_yVXE4SGlSVWtyOXc/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 05.56
A - 122130108 - DESI WAHYU EKASARI

TUGAS 4

https://drive.google.com/drive/my-drive
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 06.08
B-122130165-Abdul Ghaniy

Tugas 5

Zi – 1 = 26
A = 13
C = 7
M = 30 x 2 x 1 = 60

Z(1) = (a x Zi – 1 + c) mod M
= (13 x 26 + 7) mod 60
= 45

Z(2) = (a x Zi – 1 + c) mod M
= (13 x 45 + 7) mod 60
= 112
= 12

Z(3) = (a x Zi – 1 + c) mod M
= (13 x 112 + 7) mod 60
= 23

https://drive.google.com/file/d/0B2NhGUCg1vSEN1oyZkhvSGdBb0U/view?usp=sharing
BalasHapus
Balasan
pangga dwi t25 Oktober 2015 pukul 06.33
C_122130170_Pangga Dwi Triswendi
Tugas 5
tanggal lahir: 3
a= 13
c = 7
m= 30 x 2 x SK = 30 x 2 x 4 = 240

Z1= (13 x 3 + 7) mod 240 = 46
Z2 = (13 x 46 + 7) mod 240 = 125
Z3 = (13 x 125 + 7) mod 240 = 1

https://drive.google.com/file/d/0B75Iv2LLoZwscEs5T2xEdnU3TXM/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 06.47
A-122130040-Dimas Panji P

Zi-1 = 29
a = 13
c = 7
m = 30x2x1(stasiun kerja)

Z(1) = (13.29+7) mod 60
= 384 mod 60
= 24

Z(2) = (13.24+7) mod 60
= 319 mod 60
= 19

Z(3) = (13.19+7) mod 60
= 254 mod 60
= 14
https://drive.google.com/open?id=0B2g7T69A0kekMVM0NVpZWDZNTW8
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 06.50
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 06.57
A_122130040_Dimas Panji P

Zi-1 = 31 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

Z(1)= (a x Zi-1 + c) mod m
=(13 x 31 + 7) mod
= 410 mod 60
= 50

Z(2) = (a x Zi-1 + C) mod m
= (13 x 50 + 7) mod 60
= 657 mod 60
= 57

Z(3) = (a x Zi-1 + C) mod m
= (13 x 57 + 7) mod 60
= 748 mod 60
= 28

https://drive.google.com/open?id=0B2g7T69A0kekQXdpbWI3U3ZHNlU
BalasHapus
Balasan
pradeas25 Oktober 2015 pukul 07.45
A_122130032_Pradeas Ridiasa

Diketahui :
Tanggal lahir 27 Februari 1995
Zi-1 = 27
a = 13
c = 7
m = 30 x 2 x SK = 30 x 2 x 3 = 180
Z(i) = (a x Zi-1 +c) mod m
Z(1) = (13 x 27 + 7) mod 180
= 358 mod 180
= 178
Z(2) = (13 x 178 + 7) mod 180
= 2321 mod 180
= 161
Z(3) = (13 x 161 + 7) mod 180
= 2100 mod 180
= 120

https://drive.google.com/open?id=0B-qXzmlpw_StRUxUYVVOc3E0N1k
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 08.21
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 08.31
B-122130204-Luthfi Hadinata
Zi-1 = 11 Desember 1995 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

Z(1)= (a x Zi-1 + c) mod m
=(13 x 11 + 7) mod 60
= 150 mod 60
= 30

Z(2) = (a x Zi-1 + C) mod m
= (13 x 30 + 7) mod 60
= 397 mod 60
= 37

Z(3) = (a x Zi-1 + C) mod m
= (13 x 37 + 7) mod 60
= 488 mod 60
= 8

https://drive.google.com/file/d/0BwLRHSHEZTWmYXY1b2hGNDV0T0k/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 08.31
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 08.41
A_122130016_Budi Siswanto
Zi-1 = 22 Juni 1996 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

Z(1)= (a x Zi-1 + c) mod m
=(13 x 22 + 7) mod 60
= 293 mod 60
= 53

Z(2) = (a x Zi-1 + C) mod m
= (13 x 53 + 7) mod 60
= 696 mod 60
= 96

Z(3) = (a x Zi-1 + C) mod m
= (13 x 96 + 7) mod 60
= 1255 mod 60
= 55

https://drive.google.com/file/d/0B6gQrShd_igiTEFoTmJDbXQxeHc/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 09.08
D - 122130044 - Eka Parmawati

https://drive.google.com/file/d/0ByVlQLSq0fnTZkhYQmJWZ01DTmc/view?usp=sharing
BalasHapus
Balasan
M Jamhur Mozart25 Oktober 2015 pukul 09.40
A_122130237_237

https://drive.google.com/file/d/0BzDWPvsSsKJTeGYzdTF5OTgtSjg/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 09.56
A_1222130063_DESTA AISYIAH
Zi-1 = 11
a = 13
c = 7
m = 30 x 2 x 3(stasiun Kerja) = 180

Z(1)= (a x Zi-1 + c) mod m
=(13 x 11 + 7) mod 180
= 150 mod 180
= 150

Z(2) = (a x Zi-1 + C) mod m
= (13 x 150 + 7) mod 180
= 1957 mod 180
= 157

Z(3) = (a x Zi-1 + C) mod m
= (13 x 157 + 7) mod 180
= 2048 mod 180
= 68

https://drive.google.com/file/d/0ByRv4jjzuCp1aEM3aVJQcEZmUU0/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 09.57
B_122130169_Revo Adi Setiono
Tanggal Lahir : 15
Zi-1 = 15
a = 13
c = 7
M = 30 x 2 x 1 = 60
Zi = (a x Zi-1 + c) mod m
Z(1) = (13x15+7) mod 60 = 22
Z(2) = (13x16+7) mod 60 = 35
Z(3) = (13x17+7) mod 60 = 48
https://drive.google.com/file/d/0B6AV7dGO2oXqQTVCbGcyeDVYYTA/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 10.14
B_122130246_Raafi Nur R.

https://drive.google.com/file/d/0B0bJi8o4tEPKOGN3anpoWTVwdzA/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 10.44
B - 122130134 - Eko Safron Y
Tugas 5

Tanggal lahir = 11
Zi-1 = 11
a = 13
c = 7
M = 30 x 2 x 1 = 60
Zi = (a x Zi-1 + c) mod m
Z(1) = =(13 x 11) + 7 mod 60
= 150 mod 60
= 30
Z(2) = (13 x 30) + 7 mod 60
= 397 mod 60
= 37
Z(3) = (13 x 37) + 7 mod 60
= 488 mod 60
= 8

https://drive.google.com/file/d/0B7vN8Zr_7xpYaDk5V2lYMWtDY1U/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 10.57
A_122130248_Ria Melliyana Purba
REVISI TUGAS 5

Zi-1 = 7 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 2 = 120

Z1 = (a x Zi-1 + c) mod M
= (13 x 7 + 7) mod 120
= 98

Z2 = (a x Zi-1 + c) mod M
= (13 x 98 +7) mod 120
= 81

Z3 = (a x Zi-1 + c) mod M
= (13 x 81 + 7) mod 120
= 40

https://drive.google.com/file/d/0B0jx_vrxYRCOMXVTUEE1dWFjMmM/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 11.49
B - 122130279 - Muhammad Agung Susanto

Keterangan

Zi-1 = 8 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

z1= (13 x 8 + 7) mod 60
z1= (111) mod 60
z1 = 51

z2= (13 x 51+ 7) mod 60
z2= (670) mod 60
z2 = 10

z3= (13 x 10+ 7) mod 60
z3= (137) mod 60
z3 = 17

https://drive.google.com/file/d/0B1EzXcDICK59Q1JnamduTjFIMnM/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 11.49
B - 122130279 - Muhammad Agung Susanto

Keterangan

Zi-1 = 8 (Tanggal Lahir)
a = 13
c = 7
m = 30 x 2 x 1(stasiun Kerja) = 60

z1= (13 x 8 + 7) mod 60
z1= (111) mod 60
z1 = 51

z2= (13 x 51+ 7) mod 60
z2= (670) mod 60
z2 = 10

z3= (13 x 10+ 7) mod 60
z3= (137) mod 60
z3 = 17

https://drive.google.com/file/d/0B1EzXcDICK59Q1JnamduTjFIMnM/view?usp=sharing
BalasHapus
Balasan
Arranda25 Oktober 2015 pukul 12.19
B_122130156_Arranda Syahfitra Siregar
TUGAS 5

Zi-1 = 1 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 1 = 60

Z1 = (a x Zi-1 + c) mod M
= (13 x 1 + 7) mod 60
= 20

Z2 = (a x Zi-1 + c) mod M
= (13 x 20 +7) mod 60
= 27

Z3 = (a x Zi-1 + c) mod M
= (13 x 27 + 7) mod 60
= 58

https://drive.google.com/file/d/0Bz-PJ6hUJh4EY0tDWTBGRE5RazA/view?usp=sharing
BalasHapus
Balasan
Nado Elmana raiZ25 Oktober 2015 pukul 12.46
b-122130100-NADO ELMANA RAIZ
TUGAS 5
Tanggal lahir = 2
Zi-1 = 2
a = 13
c = 7
M = 30 x 2 x 1 = 60

Zi = (a x Zi-1 + c) mod m
Z(1) = =(13 x 2) + 7 mod 60
= 33 mod 60
= 33
Z(2) = (13 x 33) + 7 mod 60
= 436 mod 60
= 16
Z(3) = (13 x 16) + 7 mod 60
= 215 mod 60
= 35

https://drive.google.com/open?id=0B-zl2sWcG65fV0Q5RFowT2ZDbVU
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 13.08
A_122130256_Wayan Rendy Armilando
revisi Tugas 5

Zi-1 = 26 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 2 = 120

Z1 = (a x Zi-1 + c) mod M
= (13 x 26 + 7) mod 120
= 105

Z2 = (a x Zi-1 + c) mod M
= (13 x 105 +7) mod 120
= 52

Z3 = (a x Zi-1 + c) mod M
= (13 x 52 + 7) mod 120
= 83

https://drive.google.com/file/d/0B5lM4Ky3KtvJeHV2NkVLam1GRmc/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 13.54
A_122130185_Alfin Pradika Putra
Tugas 5

Zi-1 = 16 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 4 = 240

Z1 = (a x Zi-1 + c) mod M
= (13 x 16 + 7) mod 240
= 215

Z2 = (a x Zi-1 + c) mod M
= (13 x 215 +7) mod 240
= 162

Z3 = (a x Zi-1 + c) mod M
= (13 x 162 + 7) mod 240
= 193

https://drive.google.com/file/d/0B74JMtglm9b3Y0VQRnVjWGhEVkU/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 14.27
B_122130192_Wahyu Dwi Putra
Tugas 5

Zi-1 = 26 (tanggal lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 3 = 180

Z1 = (a x Zi-1 + c) mod M
= (13 x 26 + 7) mod 180
= 345

Z2 = (a x Zi-1 + c) mod M
= (13 x 345 +7) mod 180
= 165

Z3 = (a x Zi-1 + c) mod M
= (13 x 165 + 7) mod 180
= 172

https://drive.google.com/file/d/0B2tIUQDzWwrLU1ZobHNkWTVXZjQ/view?usp=sharing
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 16.11
B-122130136-Puji Noor Rahmadi

Zi-1 = 19 (Tanggal Lahir)
a = 13
c = 7
M = 30 x 2 x jml SK = 30 x 2 x 1 = 60

Z1 = (a x Zi-1 + c) mod M
= (13 x 19 + 7) mod 60
= 14

Z2 = (a x Zi-1 + c) mod M
= (13 x 14 +7) mod 60
= 9

Z3 = (a x Zi-1 + c) mod M
= (13 x 9 + 7) mod 60
= 4
https://drive.google.com/open?id=0B2zrhFEu3nz8bkU2eWhiVEphbVU
BalasHapus
Balasan
Unknown25 Oktober 2015 pukul 17.51
Komentar ini telah dihapus oleh pengarang.
BalasHapus
Balasan